3/5 (2-12x) + 2/3 (8x+10) = 1/6 (2x-14) , dibantu kawan

Materi Aljabar
[tex] \displaystyle \frac{3}{5} (2 - 12x) + \frac{2}{3} (8x+10) = \frac{1}{6}(2x-14) \\ \text{Kalikan 30 di kedua ruas} \\ 18(2-12x) + 20(8x+10) = 5(2x-14) \\ 36 - 216x + 160x + 200 = 10x - 70 \\ -56x = -306 \\ x = \frac{306}{56} = \frac{153}{58} [/tex]