teknik integral subsitusi (2x+2)(x^2+2x+3)^6 dx

integral (2x + 2) (x^2 +2x +3 )^6 dx
misal u = x^2 + 2x + 3
du/dx = 2x + 2. ==» dx = du / (2x + 2)
= integral (2x +2) u^6 du / (2x+2)
= integral u^6 du
= u^7 /7 + c
= ( x^2+2x+3)^7 / 7 + c. semoga membantu..!