Matematika

Pertanyaan

Jika p=2 3/4,q=1 5/12,dan r=2/3,maka nilai p²+pq+pr

1 Jawaban

  • p = 11/4
    q = 17/12
    r = 2/3

    p^2 + pq + pr =
    = (11/4)^2 + (11/4)(17/12) + (11/4)(2/3)
    = (121/16) + (187/48) + (11/6)
    = (363/48) + (187/48) + (88/48)
    = 319/24

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