x + 2y = -4 || 2x + z = 5 || y - 3z = -6 || degan cara persamaan linear

x+2y=-4 ... (1)
2x+z=5. ... (2)
y-3z=-6. ... (3)

Eliminasi (1)&(2);
x+2y=-4. → kali 2
2x+z=5. → kali 1
..................................
2x+4y=-8
2x+z=5
________-
4y-z=-13. ... (4)

Eliminasi (3)&(4);
y-3z=-6 → kali 1
4y-z=-13. → kali 3
.................................
y-3z=-6
12y-3z=-39
__________-
-11y=-33
y=3

Substitusi y=3 ke (1);
x+2y=-4 → x+2(3)=-4 → x=-4-6 → x=-10

Substitusi x=-10 ke (2);
2x+z=5 → 2(-10)+z=5 → z=5+20 → z=25

Jadi diperoleh x=-10, y=3, dan z=25.

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