persamaan garis yg melalui (2,1) dan sejajar dgn garis x/4-y/3=1, dapat ditulis?

Persamaan garis yg mlalui (x1,y1) dan SEJAJAR garis ax + by + c = 0 :

ax + by = ax1 + by1

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melalui (x1,y1) = (2,1)
sejajar 1/4 x - 1/3 y - 1 = 0
a = 1/4 ; b = -1/3

Persamaan garis :
1/4 x - 1/3 y = (1/4)(2) + (-1/3)(1)
1/4 x - 1/3 y = 2/4 - 1/3
Kedua rua kalikan 12
3x - 4y = 6 - 4
3x - 4y = 2