diketahui 2log3 =× dan 2log10=y berapakah nilai 6log120

6log 120 = log 120 / log 6
= log (3.4.10)/ log (2.3)
= ( log 3 + log 4 + log 10 ) / (log 2 + log 3 )
= ( log 3 + log 2^2 + log 10) /( log 2 + log )
ganti bilangan pokok logariitma dengan 2'
= (2log3+2.2log2+2log10 ) / (2log2+2log3)
= (x + 2 + y) / (1 + x)
= ( x + y +2 ) / ( x + 1 )




=