Limit x>0 (sin4x/x^2tan2x - 2/x^2)
Matematika
AthallahArsyaf
Pertanyaan
Limit x>0 (sin4x/x^2tan2x - 2/x^2)
1 Jawaban
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1. Jawaban Anonyme
limit [ sin 4x / x² tan 2x - 2/x²]
x→0
limit [ 2 sin 2x cos 2x . cos 2x / x² sin 2x - 2/x²]
x→0
limit [ 2 cos² 2x / x² - 2/x²]
x→ 0
limit [ 2 cos² 2x - 2 ] /(x²)
x→0
limit 2 ( cos² 2x - 1) /(x²)
x→0
limit - 2sin² 2x /(x²)
x→ 0
= -2(2)² =-8