Matematika

Pertanyaan

Limit x>0 (sin4x/x^2tan2x - 2/x^2)
Limit x>0 (sin4x/x^2tan2x - 2/x^2)

1 Jawaban

  • limit [ sin 4x / x² tan 2x  -  2/x²]
    x→0

    limit [ 2 sin 2x cos 2x . cos 2x / x² sin 2x  -  2/x²]
    x→0

    limit [ 2 cos² 2x / x²  - 2/x²]
    x→ 0

    limit [ 2 cos² 2x - 2 ] /(x²)
    x→0

    limit  2 ( cos² 2x  - 1) /(x²)
    x→0

    limit - 2sin² 2x /(x²)
    x→ 0

    = -2(2)² =-8