9^(x-1 )= (1)/(\sqrt(3)), 4x + 6 =
Matematika
Fauzee26
Pertanyaan
9^(x-1 )= (1)/(\sqrt(3)), 4x + 6 =
1 Jawaban
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1. Jawaban Anonyme
9^x-1 = 1/√3
9^(x-1) = (3)^(-1/2)
3^2(x-1) = 3^(-1/2)
2(x-1)= - 1/2
x- 1 = -1/4
x = 1 - 1/4 = 3/4
Nilai 4x + 6 = 4(3/4) + 6 = 9