2^log a + 2^log b = 12 dan 3.2^log a - 2^log b = 4 maka a+b = ??? a. 144 b. 272 c. 528 d. 1.204 e .1.040 Skrng di kumpulim tolong dong...

^2log ab=12
2^12=ab
a=2^12/b
^2log a^3/b=4
2^4=a^3/b
16b=a^3
b=a^3/2^4
a=(16b)^1/3
2^12/b = 2^4/3.b^1/3
b^4/3=2^12/ 2^4/3
b^4/3=2^32/3
b^4/3=(2^8)^4/3
b=2^8=256
a=2^12/2^8=2^4=16
a+b=256+16=272