hitunglah luas daerah antara dua kurva yang fiketahui y= x^2-7x+10 dan y=2-x

InTegraL
>> Luas

Batas IntegraL
y2 = y1
x² - 7y + 10 = 2 - x
x² - 6x + 8 = 0
(x - 2)(x - 4) = 0
x = 2 ; x = 4

∫(y1 - y1) dx [4...2]
= ∫(2 - x - (x² - 7x + 10)) dx
= ∫(-x² + 6x - 8) dx
= -x³/3 + 3x² - 8x
= (-64/3 + 48 - 32) - (-8/3 + 12 - 16)
= -56/3 + 20
= -18 2/3 + 20
= 1 1/3 satuan luas

Cara Lain :
y = y
x² - 6x + 8 = 0
a = 1
b = -6
c = 8

D = b² - 4ac = 4

Luas = L = D√D /6a²
L = 4√4 /6
L = 4/3
L = 1 1/3 satuan luas