2 log (x2-2x-23)= 3 log (x2-2x-23)

LogAritMa

a'log f(x) = b'log f(x)
f(x) = 1
••
²log (x² - 2x - 23) = ³log (x² - 2x - 23)
x² - 2x - 23 = 1
x² - 2x - 24 = 0
(x - 6)(x + 4) = 0
x = 6 atau x = -4

Nilai x yg memenuhi :
x = 6 dan x = -4