Niai X yang memenuhi x-4/x-4 <= x-3/x-2 Bantuanya

x-4/x-4 <= x-3/x-2
(x-4/x-4) - (x-3/x-2) <= 0
((x-4)(x-2) - (x-3)(x-4)) / (x-4)(x-2) <=0
( (x²-6x+6) - (x²-7x+12) ) / (x-4)(x-2) <= 0

( x-6 ) / ((x - 4)(x-2)) <= 0

[1] x-6 = 0
x = 6

[2] x-4 = 0
x = 4

[3] x-2 = 0
x = 2

- + - +
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2. 4. [6.]

karena bentuk pecahan a/b, b≠0 maka x≠2 dan x≠4

karena soal tadi <=0 maka ambil bagian negatif

HP= {x| x < 2 atau 4 < x <= 6, x elemen real}