4x-3y-10=0 dan 2x-5y+2=0 tentukan himpunan penyelesaian sistem persamaan berikut.dengan cara subsitusi

Materi : SPLDV

4x - 3y - 10 = 0
2x - 5y + 2 = 0

4x - 3y = 10
2x - 5y = -2 》 2x = -2 + 5y 》 x = (-2+5y)/2

4x - 3y = 10
4((-2+5y)/2) - 3y = 10
(-8+20y)/2 - 3y = 10
(-8 + 20y) / 2 - 6y/2 = 10
(-8 + 20y - 6y ) / 2 = 10
(-8 + 14y)/2 = 10
-8 + 14y = 20
14y = 20 + 8
14y = 28
y = 28/14
y = 2

2x - 5y = -2
2x - 5(2) = -2
2x - 10 = -2
2x = -2 + 10
2x = 8
x = 8/2
x = 4

Hp = { 4 , 2 }

4x-3y-10=0 → 3y=4x-10 → y=(4x-10)/3. .... (1)
Substitusi (1) ke 2x-5y+2=0;
2x-5(4x-10/3)+2=0
2x-20x/3+50/3+2=0 (kedua rusa dikali 3)
6x-20x+50+6=0
-14x+56=0
-14x=-56
x=4

Substitusi nilai x=4 ke (1)
y=(4(4)-10)/3=6/3=2

HP = { 4, 2 }

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