Matematika

Pertanyaan

Buktikan!

Tan^2 A. Csc^2 A = sec^2 A

Sec A. Tan (90 derajat - A) = csc A

Nyepam. Saya laporkan!

2 Jawaban

  • Materi : Identitas Trigonomteri
    Kelas : XI SMA MIPA

    1 . [][]
    tan^2 A . csc^2 A = sec^2 A
    (sin^A/cos^2 A) × (1/sin^2 A) = sec^2 A
    1/cos^2 A = sec^2 A
    sec^2 A = Sec^2 A

    Terbukti ....

    2. [][]
    Sec A . tan (90 ° - A ) = csc A
    sec A . cot A = csc A
    (1/cos A) . (cos A / sin A) = csc A
    1/sin A = csc A
    csc A = csc A

    Terbukti ....
  • 1.
    tan² A * csc² A = sec² A
    sin² A /cos² A* 1/sin² A = sec² A
    1/cos²A = sec² A
    sec² A = sec² A
    (TERBUKTI)


    2.
    sec A * tan(90-A) = csc A
    1/cos A * cot A
    1/cos A * cos A/sinA
    = 1/sinA
    = csc A
    (TERBUKTI)

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