Matematika

Pertanyaan

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Hellllppppppp mtkkkkkkk

1 Jawaban

  • cos∅ = -2/3, 90°< ∅<180° -> Kuadran II

    Cos ∅= samping/miring = - 2 /3

    Samping = 2
    miring = 3
    depan = √3² - 2² = √9 - 4 = √5

    Tan∅= √5 / 3 = 1/3√5

    Karena letaknya ada di kuadran II berarti Tan∅ = -1/3√5 (B)