tolong bantu jwb ya mksh

n(S)= 50
n(A) = 19
n(B) = 21
n(C) = 10
n(AnB) = 10
n(BnC)= 7
n(AnC) = 6
n(AnBnC) = 4

b) banyak anak yg tidak menyukai ketiganya
n(AUBUC)' = n (S) - n (AUBUC)
n(AUBUC)' = 50 - [ 19+21+19 + 4 - 10 - 7- 6 ] = 50-40 = 10